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3 Comments Already

mygif
SnizzleDizzle Said,
February 5th, 2011 @8:42 pm  

1. How do you find the area of a square? Multiply the side length by itself. So, the side length is x+1. And the area is 6. So:

(x+1)(x+1) = 6
x^2 + 2x + 2 = 6

Put this in quadratic form:

x^2 + 2x – 4 = 0

Solve using quadratic formula

x = 1.2361, -3.2361

Obviously the side length is not negative, so the answer is 1.2361.

2. Let x=length of building, y=width of building.

x+y = 50 (perimeter)
x*y = 160 (area)

Substitute:

x+y=50
y=50-x

xy=160
x(50-x)=160
50x – x^2 = 160
-x^2 + 50x – 160 = 0

Solve for x using quadratic equation:

x = 3.4361, 46.5644

Looks like there might be two solutions to this problem. Let’s find y in both cases:

xy=160
3.4361y=160
y=46.5644

xy=160
46.5644y=160
y = 3.4361

So, the answer is yes, you can design a building with a perimeter of 50 and area of 160. The dimensions of the base would have to be 3.4361 x 46.5644.

mygif
JORGE4821 Said,
February 5th, 2011 @9:41 pm  

YEA WHAT HE SAID

mygif
jrrymiller Said,
February 5th, 2011 @9:51 pm  

Whoops. SnizzleD made a mistake x+y=25 not fifty.

a building 46 by 3 does not have a perimeter of 50

It is the correct technique though.

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